52/3k=-35/3k^2-4

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Solution for 52/3k=-35/3k^2-4 equation: 


k in (-oo:+oo)

(52/3)*k = (-35/3)*k^2-4 // - (-35/3)*k^2-4

(52/3)*k-((-35/3)*k^2)+4 = 0

(35/3)*k^2+(52/3)*k+4 = 0

35/3*k^2+52/3*k+4 = 0

DELTA = (52/3)^2-(4*4*35/3)

DELTA = 1024/9

DELTA > 0

k = ((1024/9)^(1/2)-52/3)/(2*35/3) or k = (-(1024/9)^(1/2)-52/3)/(2*35/3)

k = -2/7 or k = -6/5

k in { -6/5, -2/7 }

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